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Anonymous
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09/11/2021 3:35 PM
200 B
15
Indexable
def fun(n):
if n == 1:
return 'YES'
if n < 1 or n % 3 != 0:
return 'NO'
return fun(n // 3)
q = int(input())
print(fun(q))Editor is loading...
def fun(n):
if n == 1:
return 'YES'
if n < 1 or n % 3 != 0:
return 'NO'
return fun(n // 3)
q = int(input())
print(fun(q))