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##
## Bai kiem tra 1 - Thuc hanh Ly thuyet Thong ke
## Nhom 2 - Thu 3 - tiet 1-2
##
## Ho ten : Nguyen Trung Duc - MSSV : 21110269
##
# #*****************************************
## Bai 1:
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a <- matrix(data=c(1,2,3,2,2,2,3,2,3), nrow=3, ncol=3, byrow=T)
a
b <- matrix(data=c(1,-1,3,6,-2,-3,5,1,0,2,7,4,0,1,5), nrow=3, ncol=5, byrow=T)
b
# 1.1
b[, 3]

B.row2.vec <- b[2, c(1, 4, 5)]

# 1.2
a %*% b

# 1.3
ta <- t(a)
ta
tb <- t(b)
tb
ta %*% tb

# 1.4
?solve
X <- solve(a, matrix(data=c(1,1,1), byrow=T))
X


## Bai 2:
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# 2.1
count.nb.ex2 <- function(Nmax.ex2, a, b) {
  n <- 1
  count <- 0
  while (n < Nmax.ex2) {
    if (n %% a == 0 & n %% b == 0) {
      count <- count + 1
      last <- n
    }
    
    n <- n + 1
  }
  answer <- c(count, last)
  return(answer)
}
count.nb.ex2(150, 3, 4)


# 2.2
Month <- c(1:12)
Month
Nb <- c(55,62,24,34,81,29,65,48,75,82,90,66)
Nb
mydf <- data.frame(Month, Nb)
mydf

# 2.3
data <- read.csv('E:/21110269/data01.csv')
data
attach(data)
group <- Age
group1 <- group[Age <= 60]
group1
group2 <- group[Age >= 61 & Age <= 80]
group2
group3 <- group[Age > 80]
group3
Number <- c(group1, group2, group3)
Number

## Bai 3:
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# 3.1
MassProb.ex3.1 <- function(k, n, p) {
  return(choose(n, k) * p^k * (1-p)^(n-k))
}
MassProb.ex3.1(2, 4, 0.5)

# 3.2
cdf.ex3.1 <- function(X, x) {
  
}
cdf.ex3.1()





## Bai 4:
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