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4 years ago
695 B
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SELECT submission_date, (SELECT COUNT(DISTINCT hacker_id) FROM submissions s2 WHERE s2.submission_date = s1.submission_date AND (SELECT COUNT(DISTINCT s3.submission_date) FROM Submissions s3 WHERE s3.hacker_id = s2.hacker_id AND s3.submission_date < s1.submission_date) = DATEDIFF(s1.submission_date , '2016-03-01')) , (SELECT hacker_id FROM submissions s2 WHERE s2.submission_date = s1.submission_date GROUP BY hacker_id ORDER BY COUNT(submission_id) DESC , hacker_id limit 1) AS max_sub, (SELECT name FROM hackers WHERE hacker_id = max_sub) FROM (SELECT DISTINCT submission_date FROM submissions) s1 GROUP BY submission_date
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