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c_cpp
2 years ago
335 B
4
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#include <iostream> #include <string> #include <cmath> using namespace std; int main() { string n,m; int n1 = 0, m1 = 0; cin >> n >> m; for (int i = 0; i < n.length(); i++) { n1 += (n[n.length()-1-i] - '0') * pow(3,i); } for (int i = 0; i < m.length(); i++) { m1 += (m[m.length()-1-i] - '0') * pow(3,i); } cout << m1 + n1; return 0; }
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