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08/02/-2024 ============================================================================= Joins: A join clause is used for combine row from two or more table ,based on arelated column between them. Different types of join 1.inner join 2. left join = left outer join 3. right join =right outer join 4. full join = full outer join 1 inner join:- return records that have matching values from both tables syntax :- select columns from table1 inner join table2 on table1.matching_column= table2.matching_column select * from customers as c inner join orders as o on c.customer_id=o.customer_id; select * from customers as c inner join orders as o on c.customer_id=o.order_id; select c.customer_id ,c.first_name,o.order_id,o.item from customers c inner join orders o on c.customer_id=o.customer_id; 2.left join:- return all records from left table and the matching records from right tables. syntax :- select columns from table1 left join table2 on table1.matching_column= table2.matching_column exa: select * from customers as c left join orders as o on c.customer_id=o.customer_id; select c.customer_id ,c.first_name,o.order_id,o.item from customers c left join orders o on c.customer_id=o.customer_id order by c.customer_id; select c.customer_id ,c.first_name,o.order_id,o.item from orders o left join customers c on c.customer_id=o.customer_id order by c.customer_id; 3.right join:- return all records from right table and the matching records from left tables. syntax: select columns from table1 left join table2 on table1.matching_column= table2.matching_column exa: select * from customers c right join orders o on c.customer_id = o.customer_id order by o.customer_id; select o.customer_id, c.first_name ,o.item,o.amount from customers c right join orders o on c.customer_id = o.customer_id order by o.customer_id; 4. full join:- return all records from both tables there is match in either left or right table. syntax:- select columns from table1 full join table2 on table1.matching_column= table2.matching_column exa: select o.customer_id, c.first_name ,o.item,o.amount from customers c full join orders o on c.customer_id = o.customer_id order by o.customer_id; _______________________________________________________________________________________________________________________________________________________ assignment: Q1.From the following tables write a SQL query to find the salesperson(s) and the customer(s) he represents. Return Customer Name, city, Salesman, commission. Q2.From the following tables write a SQL query to locate those salespeople who do not live in the same city where their customers live and have received a commission of more than 12% from the company. Return Customer Name, customer city, Salesman, salesman city, commission. Sample table: customer customer_id | cust_name | city | grade | salesman_id -------------+----------------+------------+-------+------------- 3002 | Nick Rimando | New York | 100 | 5001 3007 | Brad Davis | New York | 200 | 5001 3005 | Graham Zusi | California | 200 | 5002 3008 | Julian Green | London | 300 | 5002 3004 | Fabian Johnson | Paris | 300 | 5006 3009 | Geoff Cameron | Berlin | 100 | 5003 3003 | Jozy Altidor | Moscow | 200 | 5007 3001 | Brad Guzan | London | | 5005 Sample table: salesman salesman_id | name | city | commission -------------+------------+----------+------------ 5001 | James Hoog | New York | 0.15 5002 | Nail Knite | Paris | 0.13 5005 | Pit Alex | London | 0.11 5006 | Mc Lyon | Paris | 0.14 5007 | Paul Adam | Rome | 0.13 5003 | Lauson Hen | San Jose | 0.12
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