Untitled
unknown
python
5 months ago
1.9 kB
27
Indexable
class Caculator: def __init__(self): pass def add(self, num1, num2): return num1+num2 def subtract(self, num1,num2): return num1-num2 def multiply(self, num1,num2): return num1*num2 def divide(self,num1,num2): return num1/num2 def __display_menu(self): print('Select an option: \n 1 Add \n 2 Subtract \n 3 Multiply \n 4 Divide \n q Quit ') def __get_input(self): # Take input from the user choice = input("Enter choice(1/2/3/4,q):") # handling the quit choice if choice == 'q' or choice not in ['1', '2', '3', '4']: return choice, None,None # handling wrong number input else: num1 = float(input("Enter first number: ")) num2 = float(input("Enter second number: ")) return choice, num1,num2 # except ValueError: # print('Invalid Number') # return None, None, None def run_calculator(self): while True: self.__display_menu() choice,num1,num2 = self.__get_input() if choice == 'q': print('bye!') break elif choice == '1': print(num1,"+",num2,"=", self.add(num1,num2)) elif choice == '2': print(num1,"-",num2,"=", self.subtract(num1,num2)) elif choice == '3': print(num1,"*",num2,"=", self.multiply(num1,num2)) elif choice == '4': print(num1,"/",num2,"=" ,self.divide(num1,num2)) # elif choice == 'q': # print('You are quiting') else: print("Invalid input")
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