Untitled

 avatar
unknown
plain_text
9 months ago
1.7 kB
11
Indexable
#include <stdio.h>
#include <math.h>
#include <string.h>
#include <ctype.h>
#include <stdlib.h>

int n, m = 0, i = 0, j = 0;
char a[10][10], f[10];

void first(char c);
void follow(char c);

int main() {
    int z;
    char c, ch;
    printf("Enter the number of productions:\n");
    scanf("%d", &n);
    printf("Enter the productions (e.g., A-BC):\n");
    for (i = 0; i < n; i++)
        scanf("%s%c", a[i], &ch); 
    do {
        m = 0;
        printf("Enter the element whose First & Follow is to be found: ");
        scanf(" %c", &c); 
        first(c);
        printf("First(%c) = {", c);
        for (i = 0; i < m; i++)
            printf("%c", f[i]);
        printf("}\n");
        m = 0;
        follow(c);
        printf("Follow(%c) = {", c);
        for (i = 0; i < m; i++)
            printf("%c", f[i]);
        printf("}\n");
        printf("Continue (0/1)? ");
        scanf("%d%c", &z, &ch); 
    } while (z == 1);
    return 0;
}

void first(char c) {
    int k;
    if (!isupper(c)) 
        f[m++] = c;
    for (k = 0; k < n; k++) {
        if (a[k][0] == c) { 
            if (a[k][2] == '\0') 
                follow(a[k][0]);
            else if (islower(a[k][2])) 
                f[m++] = a[k][2];
            else 
                first(a[k][2]);
        }
    }
}

void follow(char c) {
    if (a[0][0] == c)
        f[m++] = '$';
    for (i = 0; i < n; i++) {
        for (j = 2; j < strlen(a[i]); j++) {
            if (a[i][j] == c) { 
                if (a[i][j + 1] != '\0') 
                    first(a[i][j + 1]);
                if (a[i][j + 1] == '\0' && c != a[i][0])
                    follow(a[i][0]);
            }
        }
    }
}
Editor is loading...
Leave a Comment