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#include <bits/stdc++.h> using namespace std; #define ll long long #define EPS 1e-9 #define mod 1000000007 #define over 10000000000 #define sz(m) (ll)(m.size()) #define ceil(n, m) (((n) / (m)) + ((n) % (m) ? 1 : 0)) bool sortbysecdesc(pair<int, int> &a, pair<int, int> &b) { if (a.first == b.first) return a.second > b.second; else return a.first < b.first; } #define fixed(n) fixed << setprecision(n) const ll inf = 1e18 + 5; // priority_queue<int, vector<int>, greater<int> > pq ; template <typename T = int> istream &operator>>(istream &in, vector<T> &v) { for (T &i : v) in >> i; return in; } template <typename T = int> ostream &operator<<(ostream &out, const vector<T> &v) { for (const T &x : v) out << x << ' '; return out; } void lol() { ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0); #ifndef ONLINE_JUDGE freopen("input.txt", "r", stdin), freopen("outputt.txt", "w", stdout), freopen("error.txt", "w", stderr); #endif } double log(double base, double x) { return (log(x) / log(base)); } ll ncr(ll n, ll r) { vector<ll> inv(r + 1); ll ans = 1; inv[0] = 1; if (r + 1 >= 2) inv[1] = 1; for (int i = 2; i <= r; i++) inv[i] = mod - (mod / i) * inv[mod % i] % mod; // to get 1 / (r!) for (int i = 2; i <= r; i++) ans = ((ans % mod) * (inv[i] % mod)) % mod; for (int i = n; i >= (n - r + 1); i--) ans = ((ans % mod) * (i % mod)) % mod; return ans; } int dx[4] = {1, 0, 0, -1}; int dy[4] = {0, 1, -1, 0}; ll fast_power(ll base, ll p) { if (!p) return 1; unsigned ll ret = fast_power(base, p / 2); ret = (ret * ret); if (p % 2) ret = (ret * base); return ret; } int add(ll a, ll b) { return (a + b) % mod; } ///////////// beginning of the code ////////// int main() { lol(); int n; cin >> n; ll ans = 5e18 + 5; vector<pair<ll, ll>> in(n + 2); for (int i = 0; i < n; i++) { cin >> in[i].first >> in[i].second; } in[n].first = in[0].first, in[n].second = in[0].second; in[n + 1].first = in[1].first, in[n + 1].second = in[1].second; for (int i = 0; i < n; i++) { ll ax = in[i].first, ay = in[i].second; ll bx = in[i + 1].first, by = in[i + 1].second; ll cx = in[i + 2].first, cy = in[i + 2].second; ll a = (bx - ax); ll b = (cx - ax); ll c = (by - ay); ll d = (cy - ay); ll area = (a * d - b * c); ans = min(ans, area); } cout << ans << '\n'; }
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