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#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define EPS 1e-9
#define mod 1000000007
#define over 10000000000
#define sz(m) (ll)(m.size())
#define ceil(n, m) (((n) / (m)) + ((n) % (m) ? 1 : 0))
bool sortbysecdesc(pair<int, int> &a, pair<int, int> &b)
{
if (a.first == b.first)
return a.second > b.second;
else
return a.first < b.first;
}
#define fixed(n) fixed << setprecision(n)
const ll inf = 1e18 + 5;
// priority_queue<int, vector<int>, greater<int> > pq ;
template <typename T = int>
istream &operator>>(istream &in, vector<T> &v)
{
for (T &i : v)
in >> i;
return in;
}
template <typename T = int>
ostream &operator<<(ostream &out, const vector<T> &v)
{
for (const T &x : v)
out << x << ' ';
return out;
}
void lol()
{
ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);
#ifndef ONLINE_JUDGE
freopen("input.txt", "r", stdin), freopen("outputt.txt", "w", stdout), freopen("error.txt", "w", stderr);
#endif
}
double log(double base, double x)
{
return (log(x) / log(base));
}
ll ncr(ll n, ll r)
{
vector<ll> inv(r + 1);
ll ans = 1;
inv[0] = 1;
if (r + 1 >= 2)
inv[1] = 1;
for (int i = 2; i <= r; i++)
inv[i] = mod - (mod / i) * inv[mod % i] % mod;
// to get 1 / (r!)
for (int i = 2; i <= r; i++)
ans = ((ans % mod) * (inv[i] % mod)) % mod;
for (int i = n; i >= (n - r + 1); i--)
ans = ((ans % mod) * (i % mod)) % mod;
return ans;
}
int dx[4] = {1, 0, 0, -1};
int dy[4] = {0, 1, -1, 0};
ll fast_power(ll base, ll p)
{
if (!p)
return 1;
unsigned ll ret = fast_power(base, p / 2);
ret = (ret * ret);
if (p % 2)
ret = (ret * base);
return ret;
}
int add(ll a, ll b)
{
return (a + b) % mod;
}
///////////// beginning of the code //////////
int main()
{
lol();
int n;
cin >> n;
ll ans = 5e18 + 5;
vector<pair<ll, ll>> in(n + 2);
for (int i = 0; i < n; i++)
{
cin >> in[i].first >> in[i].second;
}
in[n].first = in[0].first, in[n].second = in[0].second;
in[n + 1].first = in[1].first, in[n + 1].second = in[1].second;
for (int i = 0; i < n; i++)
{
ll ax = in[i].first, ay = in[i].second;
ll bx = in[i + 1].first, by = in[i + 1].second;
ll cx = in[i + 2].first, cy = in[i + 2].second;
ll a = (bx - ax);
ll b = (cx - ax);
ll c = (by - ay);
ll d = (cy - ay);
ll area = (a * d - b * c);
ans = min(ans, area);
}
cout << ans << '\n';
}
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