Largest Subarray with K sum
Brute Forceclass Solution { int maxLen(int arr[]) { int i, j, k; int sum, c=0, maxi=0, n=arr.length; for(i=0;i<n;++i) { for(j=i;j<n;++j) { sum = 0; c = 0; for(k=i;k<=j;++k) { sum += arr[k]; } if(sum==0) { c=j-i+1; maxi = Math.max(maxi, c); } } } return maxi; } }
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