Untitled
Anonymous
python
04/07/2024 3:22 AM
728 B
14
Indexable
ans = 0
mid = len(nums)//2
nums.sort()
if nums[mid] == k:
return 0
if nums[mid] < k:
for i in range(mid, len(nums)):
if nums[i] >= k:
break
ans += abs(k - nums[i])
return ans
if nums[mid] > k:
i = mid
while i >= 0 and nums[i] >= k:
ans += abs(k - nums[i])
i -= 1
return ansEditor is loading...
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