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python
a year ago
545 B
4
Indexable
ans = 0 mid = len(nums)//2 nums.sort() if nums[mid] == k: return 0 if nums[mid] < k: for i in range(mid, len(nums)): if nums[i] >= k: break ans += abs(k - nums[i]) return ans if nums[mid] > k: i = mid while i >= 0 and nums[i] >= k: ans += abs(k - nums[i]) i -= 1 return ans
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