Solution
unknown
javascript
4 years ago
622 B
5
Indexable
let rows = [];
let columns = [];
for(let row = 0; row < matrix.length; row++) {
for(let column = 0; column < matrix[0].length; column++) {
if (matrix[row][column] === 0) {
rows.push(row);
columns.push(column);
}
}
}
for(let column of columns) {
for(let row = 0; row < matrix.length; row++) {
matrix[row][column] = 0;
}
}
for(let row of rows) {
for(let column = 0; column < matrix[0].length; column++) {
matrix[row][column] = 0;
}
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