Solution
unknown
javascript
4 years ago
622 B
3
Indexable
let rows = []; let columns = []; for(let row = 0; row < matrix.length; row++) { for(let column = 0; column < matrix[0].length; column++) { if (matrix[row][column] === 0) { rows.push(row); columns.push(column); } } } for(let column of columns) { for(let row = 0; row < matrix.length; row++) { matrix[row][column] = 0; } } for(let row of rows) { for(let column = 0; column < matrix[0].length; column++) { matrix[row][column] = 0; } }
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