Q2

#include <stdio.h>

// Use two 2D matrices to store the temperoary result of each day
// mapA is used to store the temperoray result of each day
// mapB is used to store the result after the update, and will be used to update on mapA after everything is done each day 
int mapA[300][300], mapB[300][300];
int main() {
    // Read in the arguments
    int H, W, D;
    scanf("%d %d %d", &H, &W, &D);

    // Readin the value of each box in mapA
    for (int i = 0; i < H; i++)
        for (int j = 0; j < W; j++)
            scanf("%d", &mapA[i][j]);

    // First loop through each day 
    for (int d = 0; d < D; d++) {
        
        // The second and third will go through each box in the matrix
        for (int i = 0; i < H; i++) {
            for (int j = 0; j < W; j++) {
                
                // The first section, we are going the calculate the voting result.

                // We use three variables as the counter of each category:
                int rock = 0, paper = 0, scissor = 0;
                // Loop through the eight boxes around current box (i, j)    
                for (int di = -1; di <= 1; di++) { // di means the difference in i axis compared with current box (i, j)
                    for (int dj = -1; dj <= 1; dj++) { // dj means the difference in j axis compared with current box (i, j)
                        // Use (ti, tj) to represent the box we are going to inspect
                        int ti = i + di, tj = j + dj;
                        // Check the validity of the inspected box
                        // 1. (ti != i && tj != j): Is it NOT the current box?
                        // 2. (ti >= 0 && ti < H && tj >= 0 && tj < W): Is the value of coordinate valid?
                        if ((ti != i && tj != j) && (ti >= 0 && ti < H && tj >= 0 && tj < W)) {
                            // If all the condition is held, we will increase the counter of corresponding category 
                            if (mapA[ti][tj] == 0)
                                rock += 1;
                            else if (mapA[ti][tj] == 2)
                                scissor += 1;
                            else if (mapA[ti][tj] == 5)
                                paper += 1;
                        }
                    }
                }
                
                // In the second section, we are going to update the result to mapB based on the counters we've updated:
                // (Since it is the majority voting, we cannot use `>=` !!)
                if (rock > paper && rock > scissor)
                    mapB[i][j] = 5; // If majority is rock, update to paper
                else if (paper > rock && paper > scissor)
                    mapB[i][j] = 2; // If majority is paper, update to scissor
                else if (scissor > rock && scissor > paper)
                    mapB[i][j] = 0; // If majority is scissor, update to stone
                else
                    mapB[i][j] = mapA[i][j]; // Otherwise, copy the current value

            }
        }

        // After all the boxes are updated, we need to copy the current value back to mapA,
        // then in the next day, we can read in the correct value of each box after the voting today
        for (int i = 0; i < H; i++)
            for (int j = 0; j < W; j++)
                mapA[i][j] = mapB[i][j];
    }

    // Once we update D days, we can ouput the result of mapA
    for (int i = 0; i < H; i++) {
        for (int j = 0; j < W; j++) {
            printf("%d ", mapA[i][j]);
        }
        printf("\n");
    }

    return 0;
}