Untitled
user_9124840
plain_text
a year ago
1.0 kB
10
Indexable
class Solution {
public:
vector<int> spiralOrder(vector<vector<int>>& matrix) {
int n = matrix.size(), m = matrix[0].size();
vector<int> array;
int left = 0, right = m - 1;
int top = 0, bottom = n - 1;
while (left <= right && top <= bottom) {
for (int i = left; i <= right; ++i) {
array.push_back(matrix[top][i]);
}
top++;
for (int i = top; i <= bottom; ++i) {
array.push_back(matrix[i][right]);
}
right--;
if (top <= bottom) {
for (int i = right; i >= left; --i) {
array.push_back(matrix[bottom][i]);
}
bottom--;
}
if (left <= right) {
for (int i = bottom; i >= top; --i) {
array.push_back(matrix[i][left]);
}
left++;
}
}
return array;
}
};Editor is loading...
Leave a Comment